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How high can we count in binary?

We've counted other ways, but can we count binary? As usual, we each put one number per post. One post per 24 hours unless somebody else puts a number.

I'll start.

1

 

Related:

#1 lectraplayer, May 1, 2014
10
 
#2 iowabowtech, May 1, 2014
11
 
#3 lectraplayer, May 1, 2014
100
 
#4 iowabowtech, May 1, 2014
101
 
#5 lectraplayer, May 1, 2014
110
 
#6 iowabowtech, May 2, 2014
111

Are you the only one IBT?
 
#7 lectraplayer, May 2, 2014
1000

I'm sure the others will be rolling in any moment now. Good game idea!
 
#8 iowabowtech, May 3, 2014
1001....i think:rolleyes:
whoops! just read the 24 hr rule thingy...

that's what I get for doing math..es iz

never mind:p
 
#9 huh, May 3, 2014
1010

I'm comin'!

If somebody else counted since you, there is no clock and you can play. The 24 hour clock is only if nobody else has played since your last play.
 
#10 lectraplayer, May 3, 2014
1011
 
#11 iowabowtech, May 6, 2014
1110

I think?
 
#12 DragonSlayer95, May 6, 2014
1110 is what you meant to say.

I'll take 1111.
 
#13 lectraplayer, May 6, 2014
Time to up the ante.

10000
 
#14 iowabowtech, May 6, 2014
10001
 
#15 DragonSlayer95, May 6, 2014
10010
 
#16 lectraplayer, May 7, 2014
10011
 
#17 iowabowtech, May 7, 2014
10100
 
#18 lectraplayer, May 7, 2014
10101
 
#19 Hadron, May 7, 2014
10111
 
#20 lectraplayer, May 7, 2014
10111
 
#21 iowabowtech, May 7, 2014
11000

Well, we've messed up somewhere...
 
#22 palmtree5, May 7, 2014
11001
 
#23 iowabowtech, May 8, 2014
11010
 
#24 DragonSlayer95, May 8, 2014
11011
 
#25 Hadron, May 8, 2014
Do you mean decimal system?

It is very easy to calculate it by yourself:
X*2^Y where X is either 0 or 1 and Y is a running number starting from 0 from the right.

1100(2) = 0*2^0 + 0*2^1 + 1*2^2 + 1*2^3 = 12(10)

Or if you remember the serie:
1,2,4,8,16,32,64,128,256,512,1024,2048,4096,... it is even easier..
 
#150 mrex, Apr 16, 2017